If log x= log a - 2log b, then express x in terms of a, b, and c??

x = c-c+a/(b^2)


why you need to drag c into the equation is beyond me.

If log x= log a - 2log b, then express x in terms of a, b, and c??
I'm a law student because I hate math.
Reply:X=10^(a/b^2)