Calculate q when 5.32 g of ice is cooled from -37.8°C to -76.3°C (c of ice = 2.087 J/g·K).?

Calculate q when 5.32 g of ice is cooled from -37.8°C to -76.3°C (c of ice = 2.087 J/g·K). Express your answer in scientific format: 1.25 x 103 = 1.25E3

Calculate q when 5.32 g of ice is cooled from -37.8°C to -76.3°C (c of ice = 2.087 J/g·K).?
q = m x Cp x ∆T





∆T = (-37.8 + 273.15) - (-76.3 + 273.15) = 235.35 - 196.85 = 38.5K





= 5.32 g x (2.087 J / gK) x (38.5K)) = 427.5 J = 4.275 x 10² J





since you have only three sig figs....





answer is 4.28 x 10² J