Can anyone express 5logc x+logcy-2logcz as a single logarithm?
That c is below the log (kind of like square root is above a number).
Can anyone express 5logc x+logcy-2logcz as a single logarithm?
logc(x^5*y/z^2)
Reply:logc ((x^5y)/z^2).
That is, x to the 5th power times y, all divided by z squared.
daisy
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