Given A = BeC, which of the following correctly express the natural logarithm of this equation?

Given A = BeC, which of the following correctly express the natural logarithm of this equation? (Select all that apply.)


lnA = lnB + C


ln(A/B) = C


lnA - lnB = C


lnA = lnB - C


lnA = lnB x lnC





I'm not entirely sure how they go together, ive never seen it in this format. It later asks to solve for C in 5 = 7e^C. Help?

Given A = BeC, which of the following correctly express the natural logarithm of this equation?
http://www.purplemath.com/modules/solvel...


This should help. It's been a WHILE.
Reply:I assume you mean A=Be^C (where e is raised to the C power)?





If so, here's how you solve for C:





Divide by B





A/B = e^C


Take the natural log (ln) of each side





ln(A/B) = ln e^C





Based on the inverse property of ln and e, ln e^C = C





ln (A/B) = C