Can anyone express 5logc x+logcy-2logcz as single logarithm
That c is below the log (kind of like square root is above a number).
Can anyone express 5logc x+logcy-2logcz as single logarithm?
logc [(x^5)y/(z^2)]
Reply:5log(c)x + log(c)y - 2log(c)z
log(c)(x^5) + log(c)y - log(c)(z^2)
log(c)((x^5y)/(z^2))
Reply:logc(x^5y/z^2). Use your log rules to simplify it. Addition of logs is same as multiplication inside the log, and subtraction is division. A constant as in n log (a) would be log(a^n).
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