Okay this might be a easy problem, and maybe i just cant concentrate but i dont get this, its the last question to my math hw here we go....
A farmer can plow a field in d days. It takes his son 4 fewer days to the plow the same field.
a) Express in terms of d the part of the field that the farmer can plow in a day.
b) Express in terms of d the part of the field that the son can plow in a day
c) Express as a fraction in lowest terms the part of the field that the farmer and his son can plow in a day working together.
Those are the 3 questions (a,b,c), a brief explanation of how you arrived at the answer for each would be appreciated, anyways thanks for helping..
Math gets on my nerves sometimes, help with this problem pls thx?
a) If the farmer takes 2 days then in one day it would be 1/2 the field, if he takes 3 days then in one day it would be 1/3 so if he takes d days in one day it would be 1/d
b) 1/(d-4) - as above
c) Add these 2 together and you get what is achieved in 2 days - so in one day, it would be half of that
Reply:"Lulu 49" is fine until the last answer...there is no logic in dividing by 2....if dad can do 1/10th and son then 1/6th then adding together and dividing by 2 implies together they do less than the son by himself....hmm...maybe that was Lulu's logic
Reply:There are two possible approaches to solving a homework problems you don't get. One is to look at the examples earlier in the chapter and see if you can find one that resembles it. The other is to look at the problems around it (this works particularly well if the textbook has answers to the odd questions in the back). If you can figure out how to solve a similar problem, you can solve this one too.
Another approach is to throw in a number instead of "d" in order to get a better feel for what the answer should look like. If you use something like 3, which means that it takes the farmer 3 days to plow the entire field, then in 1 day he can plow 1/3 of the field, right?
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