How much heat is released as the temperature of 10.7 grams of copper tubing is decreased from 45.8°C to 95.7°C? The specific heat of copper is 0.385 J/g-°C.
Express your answer to the nearest joule.
I have other questions so if you'd like go answer those. The first good answer gets 10 points.
Chemistry Question.?
10.7g x 0.385J/g/°C x 49.9°C ΔT
= 206 Joules of heat released.
Reply:E= mCpdT
Ti= 45.8ºC, Tf = 95.7ºC dT = Tf-Ti = 49.9ºC
E = 10.7g * (0.385J/JºC) * - 49.9ºC = 205.5J or 206 J
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