Chemistry Question?

How much heat is required to raise the temperature of 11.7 grams of water from 42.8°C to 96.1°C? The specific heat of water is 1.00 cal/g-°C.





Express your answer in calories as three significant digits





I have other questions so if you'd like go answer those. The first good answer gets 10 points.

Chemistry Question?
You have the answer right in front of you. Just apply common sense.





Sp Heat of water is 1.00cal/g*C right





we want to raise the temperature (96.1-42.8) = 53.3*C.


Sooo.





53.3*C x 11.7g = 623.61calories





Our final answer is therefore 624calories
Reply:heat added= (specific heat)(mass)(change in temp)=





(1.00cal/g C)(11.7g)(53.3 C)= about 624 cal