Suppose the sample space consists only of elemental events A, B, C, and D. Suppose the chance of B is 28%.?

Suppose P(C) = 6/10. Suppose D is 3 times more likely than A. Find the probability of A and report it correct to 3 decimal places. Express your answer with 3 decimal places – e.g., .2 should be reported as .200 and .47 should be reported as .470.

Suppose the sample space consists only of elemental events A, B, C, and D. Suppose the chance of B is 28%.?
P(B) = 28/100 = 0.28


P(C) = 6/10 = 0.6





Let P(A) = x


This implies that P(D) = 3x.





Since sum of all probabilities in a sample space = 1,


we can say that:


P(A) + P(B) + P(C) + P(D) = 1


x + 0.28 + 0.6 + 3x = 1


4x = 0.12


x = 0.03





Therefore, P(A) = 0.03 and P(D) = 3*0.03 = 0.9. ... Ans





Hope this helps.

columbine