Okay I hate LOGS please help me here!!!?

A) If log 2 = 0.3010 and log 3 = 0.4771 determine the approximate numeric value


1)log 1.5


2)log ( ^4, square root 3)








B) Expand using log laws:


1) log (3 times ^4 square root n) divide that by y squared


2) log 2x+3 divide that by 6(2x-1)x





C) Express as a single log : 2 log base 1/ 3, x ^4 and y ^2 - log base 1/3, x - 3log base1/3 y





any help will be fine thank you !!

Okay I hate LOGS please help me here!!!?
1)log 1.5


=log(3/2)=log(3)-log(2)=0.3010-0.4771=...