A triangle has base (c) and base angles 34 deg and 77 deg. Express the height of the triangle as a fn of c.?

c*sin(34)*sin(77)*/sin(69)=height


this works out to be the same as the one above me, but I like it better because most calculators dont have a cot button so you have to invert your tans--which can be a little tedious.

A triangle has base (c) and base angles 34 deg and 77 deg. Express the height of the triangle as a fn of c.?
Let h be the height.


h*cot(34)+h*cot(77) = c


Solve for h,


h = c/[cot(34)+cot(77)]

floral deliveries