What is the heat capacity of 1.97 x 10^3 g of water expressed in J/deg. C?

I need help on how to solve this problem and please, work it out.

What is the heat capacity of 1.97 x 10^3 g of water expressed in J/deg. C?
Allright let me see....To do heat Capacity Questions you must know Specific heat that is given in most equations. For water it is


gas = 2.080 Joules per gram degree kelvin


liquid = 4.1813 Joules per gram degree kelvin


solid = 2.114 Joules per gram degree kelvin


So i'm guessing your useing liquid and that the atomoshpereic pressure is normal?





So your number(1.97*10^3) times 4.1813 =8237.161 Joules per degree Kelvin





Then Kelvine to Celsius,
Reply:Simply multiply this number by 4.18.

columbine