Express the equation of the line joining two points (4,3) and (-4,8) in the form ax+by+c=0?

please help meee!!! im confused :(





thanx

Express the equation of the line joining two points (4,3) and (-4,8) in the form ax+by+c=0?
Here is how to do it:





First find the slope, use this formula: (y2-y1)/(x2-x1)


which for ur problem is (8-3)/(-4-4)= -5/8.





Then use this formula to plug in the slope and the point.(either one of the two points): y-y1=m(x-x1), m is the slope.


which for ur problem is y-4= -5/8(x-3)





Finally, convert into the ax+by=c=0 form... i'll just do this in my head. =P


This is the answer u want ====%26gt; (5/8)x+y-(11/2)=0





I'm positive this is the correct answer, btw, i'm in BC calculus...lol
Reply:1. Find the slope.





2. Use this slope and either point and use the point-slope equation. [ y - y1 = m (x - x1) ]





3. Rearrange to standard form.