Can any1 help me to express (2+surd2)/(3-surd2) in d form a+b surd c ????

plz shw all d steps.....thz =p

Can any1 help me to express (2+surd2)/(3-surd2) in d form a+b surd c ????
Hi,





2 + √2


---------


3 - √2





Multiply top and bottom by denominator's conjugate, 3 + √2.





(2 + √2)(3 + √2)


---------------------- =


(3 - √2)(3 + √2)





6 + 2√2 + 3√2 + √4


--------------------------- =


9 + 3√2 - 3√2 - √4





6 + 2√2 + 3√2 + 2


--------------------------- =


9 + 3√2 - 3√2 - 2





8 + 5√2


----------- %26lt;== ANSWER


.....7





8.......5√2


---.+.-------- %26lt;== ANSWER in a + b√c form


7.......7





I hope that helps!! :-)
Reply:(2+surd2)/(3-surd2)





= (2 + √2)/(3 - √2)


Multiply by in above (3 + √2)/(3 + √2)


= {(2 + √2)/(3 - √2)} x {(3 + √2)/(3 + √2)}


= (2 + √2)(3 + √2)/(3 - √2)(3 + √2)


= (6 + 2√2 + 3√2 + √4)/(9 + 3√2 - 3√2 - √4)


= (6 + 2√2 + 3√2 + 2)/(9 - 2)


= (8 + 5√2)/7


= (8/7) + (5√2)/7